SUB — Subtract

Instruction Word

Slot
ae2_slot0
6
3
6
2
6
1
6
0
5
9
5
8
5
7
5
6
5
5
5
4
5
3
5
2
5
1
5
0
4
9
4
8
4
7
4
6
4
5
4
4
4
3
4
2
4
1
4
0
3
9
3
8
3
7
3
6
3
5
3
4
3
3
3
2
3
1
3
0
2
9
2
8
2
7
2
6
2
5
2
4
2
3
2
2
2
1
2
0
1
9
1
8
1
7
1
6
1
5
1
4
1
3
1
2
1
1
1
0
9876543210
Format ae_format2 - 64 bit(s)0000 1110
SUB 1000000000001101 1010
r 3210
s 3210
t 3210

Slot
ae_slot0
6
3
6
2
6
1
6
0
5
9
5
8
5
7
5
6
5
5
5
4
5
3
5
2
5
1
5
0
4
9
4
8
4
7
4
6
4
5
4
4
4
3
4
2
4
1
4
0
3
9
3
8
3
7
3
6
3
5
3
4
3
3
3
2
3
1
3
0
2
9
2
8
2
7
2
6
2
5
2
4
2
3
2
2
2
1
2
0
1
9
1
8
1
7
1
6
1
5
1
4
1
3
1
2
1
1
1
0
9876543210
Format ae_format - 64 bit(s) 1111
SUB 01011010
r 3210
s 3210
t 3210

Slot
Inst
6
3
6
2
6
1
6
0
5
9
5
8
5
7
5
6
5
5
5
4
5
3
5
2
5
1
5
0
4
9
4
8
4
7
4
6
4
5
4
4
4
3
4
2
4
1
4
0
3
9
3
8
3
7
3
6
3
5
3
4
3
3
3
2
3
1
3
0
2
9
2
8
2
7
2
6
2
5
2
4
2
3
2
2
2
1
2
0
1
9
1
8
1
7
1
6
1
5
1
4
1
3
1
2
1
1
1
0
9876543210
Format x24 - 24 bit(s) 0
SUB 11000000 0000
r 3210
s 3210
t 3210

Slot
ae_slot0
6
3
6
2
6
1
6
0
5
9
5
8
5
7
5
6
5
5
5
4
5
3
5
2
5
1
5
0
4
9
4
8
4
7
4
6
4
5
4
4
4
3
4
2
4
1
4
0
3
9
3
8
3
7
3
6
3
5
3
4
3
3
3
2
3
1
3
0
2
9
2
8
2
7
2
6
2
5
2
4
2
3
2
2
2
1
2
0
1
9
1
8
1
7
1
6
1
5
1
4
1
3
1
2
1
1
1
0
9876543210
Format ae_format1 - 64 bit(s)1 1110
SUB 01011010
r 3210
s 3210
t 3210

Assembler Syntax

SUB ar, as, at

C Syntax

#include <xtensa/tie/xt_core.h>

extern int XT_SUB(int s, int t);

Description

(please consult the Xtensa ® Instruction Set Architecture Reference Manual for any cross references and additional information)

SUB calculates the two's complement 32-bit difference of address registers as and at. The low 32 bits of the difference are written to address register ar. Arithmetic overflow is not detected.

Operation

AR[r] ← AR[s] − AR[t]

Exceptions

EveryInstR Group (see EveryInstR Group:)

Implementation Pipeline

In Out
ars Estage, art Estage arr Estage

Protos that use SUB

proto SUB { out int32 r, in int32 s, in int32 t }{}{
SUB r, s, t;
}