x86: cpu: Skip init code when chain loading
When U-Boot is not the first-stage bootloader the interrupt and cache init
must be skipped, as well as init for various peripherals. Update the code
to add checks for this.
Signed-off-by: Simon Glass <sjg@chromium.org>
Reviewed-by: Bin Meng <bmeng.cn@gmail.com>
diff --git a/arch/x86/cpu/cpu.c b/arch/x86/cpu/cpu.c
index cec04b4..8526e85 100644
--- a/arch/x86/cpu/cpu.c
+++ b/arch/x86/cpu/cpu.c
@@ -239,8 +239,10 @@
struct udevice *dev;
int ret;
- if (!ll_boot_init())
+ if (!ll_boot_init()) {
+ uclass_first_device(UCLASS_PCI, &dev);
return 0;
+ }
ret = x86_init_cpus();
if (ret)
diff --git a/arch/x86/cpu/i386/interrupt.c b/arch/x86/cpu/i386/interrupt.c
index 4c7e9ea..e67a116 100644
--- a/arch/x86/cpu/i386/interrupt.c
+++ b/arch/x86/cpu/i386/interrupt.c
@@ -264,6 +264,9 @@
struct udevice *dev;
int ret;
+ if (!ll_boot_init())
+ return 0;
+
/* Try to set up the interrupt router, but don't require one */
ret = irq_first_device_type(X86_IRQT_BASE, &dev);
if (ret && ret != -ENODEV)
@@ -295,8 +298,7 @@
* TODO(sjg@chromium.org): But we don't handle these correctly when
* booted from EFI.
*/
- if (ll_boot_init())
- enable_interrupts();
+ enable_interrupts();
#endif
return 0;