log: force DEBUG when LOG_DEBUG is activated
When CONFIG_LOG is activated, if LOG_DEBUG is defined in a file and
DEBUG is not defined the trace with debug() macro are not displayed,
because the parameter cond : _DEBUG = 0 is checked in debug_cond().
With this patch the define DEBUG, used to force the trace generated by
debug() macro, is linked with the define LOG_DEBUG, used to force the
trace generated by other macros (log_debug, dev_dbg, pr_debug).
We only need to define LOG_DEBUG in a file to activate all the
traces generated by any U-Boot debug macro, as it is described in
/doc/develop/logging.rst
Signed-off-by: Patrick Delaunay <patrick.delaunay@foss.st.com>
diff --git a/doc/develop/logging.rst b/doc/develop/logging.rst
index 51095b0..704a6bf 100644
--- a/doc/develop/logging.rst
+++ b/doc/develop/logging.rst
@@ -66,26 +66,21 @@
#define LOG_DEBUG
to enable building in of all logging statements in a single file. Put it at
-the top of the file, before any #includes.
-
-To actually get U-Boot to output this you need to also set the default logging
-level - e.g. set CONFIG_LOG_DEFAULT_LEVEL to 7 (:c:data:`LOGL_DEBUG`) or more.
-Otherwise debug output is suppressed and will not be generated.
+the top of the file, before any #includes and any message in the file will be
+written, regardless of the value of CONFIG_LOG_DEFAULT_LEVEL.
Using DEBUG
-----------
U-Boot has traditionally used a #define called DEBUG to enable debugging on a
-file-by-file basis. The debug() macro compiles to a printf() statement if
-DEBUG is enabled, and an empty statement if not.
+file-by-file basis but LOG_DEBUG are intended to replace it with the logging
+facilities; DEBUG is activated when LOG_DEBUG is activated.
With logging enabled, debug() statements are interpreted as logging output
-with a level of LOGL_DEBUG and a category of LOGC_NONE.
+with a level of LOGL_DEBUG and a category of LOG_CATEGORY.
-The logging facilities are intended to replace DEBUG, but if DEBUG is defined
-at the top of a file, then it takes precedence. This means that debug()
-statements will result in output to the console and this output will not be
-logged.
+With logging disabled, the debug() macro compiles to a printf() statement
+if DEBUG is enabled and to an empty statement if not.
Logging statements
------------------