Makefile: Suppress output of python libfdt build command
This should not be printed by default. Prefix it with $(Q).
Fixes ee95d10b: ("fdt: Build the new python libfdt module")
Signed-off-by: Bin Meng <bmeng.cn@gmail.com>
diff --git a/tools/Makefile b/tools/Makefile
index 5605fa7..a0db19d 100644
--- a/tools/Makefile
+++ b/tools/Makefile
@@ -131,8 +131,8 @@
# all three files in $(obj)/tools: _libfdt.so, libfdt.py and libfdt_wrap.c
# The latter is a temporary file which we could actually remove.
tools/_libfdt.so: $(LIBFDT_SRCS) $(LIBFDT_SWIG)
- cp $(LIBFDT_SWIG) tools/.
- unset CC; \
+ $(Q)cp $(LIBFDT_SWIG) tools/.
+ $(Q)unset CC; \
unset CROSS_COMPILE; \
LDFLAGS="$(HOSTLDFLAGS)" CFLAGS= VERSION="u-boot-$(UBOOTVERSION)" \
CPPFLAGS="$(_hostc_flags)" OBJDIR=tools \