ext4: free allocations by parse_path()
parse_path() malloc()s the entries in the array it's passed. Those
allocations must be free()d by the caller, ext4fs_get_parent_inode_num().
Add code to do this.
For this to work, all the array entries must be dynamically allocated,
rather than a mix of dynamic and static allocations. Fix parse_path() not
to over-write arr[0] with a pointer to statically allocated data.
Signed-off-by: Stephen Warren <swarren@nvidia.com>
Acked-by: Lukasz Majewski <l.majewski@samsung.com>
Tested-by: Lukasz Majewski <l.majewski@samsung.com>
diff --git a/fs/ext4/ext4_common.c b/fs/ext4/ext4_common.c
index c77e22d..9fdbfe6 100644
--- a/fs/ext4/ext4_common.c
+++ b/fs/ext4/ext4_common.c
@@ -615,8 +615,7 @@
arr[i] = zalloc(strlen("/") + 1);
if (!arr[i])
return -ENOMEM;
-
- arr[i++] = "/";
+ memcpy(arr[i++], "/", strlen("/"));
/* add each path entry after root */
while (token != NULL) {
@@ -746,6 +745,11 @@
fail:
free(depth_dirname);
free(parse_dirname);
+ for (i = 0; i < depth; i++) {
+ if (!ptr[i])
+ break;
+ free(ptr[i]);
+ }
free(ptr);
free(parent_inode);
free(first_inode);