dtoc: Adjust Node to record its parent
We need to be able to search back up the tree for #address-cells and
#size-cells. Record the parent of each node to make this easier.
Signed-off-by: Simon Glass <sjg@chromium.org>
Reviewed-by: Philipp Tomsich <philipp.tomsich@theobroma-systems.com>
Tested-by: Philipp Tomsich <philipp.tomsich@theobroma-systems.com>
Tested-by: Kever Yang <kever.yang@rock-chips.com>
diff --git a/tools/dtoc/fdt.py b/tools/dtoc/fdt.py
index 63a32ea..49409a6 100644
--- a/tools/dtoc/fdt.py
+++ b/tools/dtoc/fdt.py
@@ -174,8 +174,9 @@
props: A dict of properties for this node, each a Prop object.
Keyed by property name
"""
- def __init__(self, fdt, offset, name, path):
+ def __init__(self, fdt, parent, offset, name, path):
self._fdt = fdt
+ self.parent = parent
self._offset = offset
self.name = name
self.path = path
@@ -217,7 +218,7 @@
sep = '' if self.path[-1] == '/' else '/'
name = self._fdt._fdt_obj.get_name(offset)
path = self.path + sep + name
- node = Node(self._fdt, offset, name, path)
+ node = Node(self._fdt, self, offset, name, path)
self.subnodes.append(node)
node.Scan()
@@ -279,7 +280,7 @@
TODO(sjg@chromium.org): Implement the 'root' parameter
"""
- self._root = self.Node(self, 0, '/', '/')
+ self._root = self.Node(self, None, 0, '/', '/')
self._root.Scan()
def GetRoot(self):
@@ -386,7 +387,7 @@
return libfdt.fdt_off_dt_struct(self._fdt) + offset
@classmethod
- def Node(self, fdt, offset, name, path):
+ def Node(self, fdt, parent, offset, name, path):
"""Create a new node
This is used by Fdt.Scan() to create a new node using the correct
@@ -394,11 +395,12 @@
Args:
fdt: Fdt object
+ parent: Parent node, or None if this is the root node
offset: Offset of node
name: Node name
path: Full path to node
"""
- node = Node(fdt, offset, name, path)
+ node = Node(fdt, parent, offset, name, path)
return node
def FdtScan(fname):