| /* |
| * Copyright (C) 2014 Google, Inc |
| * |
| * SPDX-License-Identifier: GPL-2.0+ |
| */ |
| |
| #include <common.h> |
| #include <dm.h> |
| #include <pch.h> |
| |
| #define GPIO_BASE 0x48 |
| #define SBASE_ADDR 0x54 |
| |
| static int pch9_get_spi_base(struct udevice *dev, ulong *sbasep) |
| { |
| uint32_t sbase_addr; |
| |
| dm_pci_read_config32(dev, SBASE_ADDR, &sbase_addr); |
| *sbasep = sbase_addr & 0xfffffe00; |
| |
| return 0; |
| } |
| |
| static int pch9_get_gpio_base(struct udevice *dev, u32 *gbasep) |
| { |
| u32 base; |
| |
| /* |
| * GPIO_BASE moved to its current offset with ICH6, but prior to |
| * that it was unused (or undocumented). Check that it looks |
| * okay: not all ones or zeros. |
| * |
| * Note we don't need check bit0 here, because the Tunnel Creek |
| * GPIO base address register bit0 is reserved (read returns 0), |
| * while on the Ivybridge the bit0 is used to indicate it is an |
| * I/O space. |
| */ |
| dm_pci_read_config32(dev, GPIO_BASE, &base); |
| if (base == 0x00000000 || base == 0xffffffff) { |
| debug("%s: unexpected BASE value\n", __func__); |
| return -ENODEV; |
| } |
| |
| /* |
| * Okay, I guess we're looking at the right device. The actual |
| * GPIO registers are in the PCI device's I/O space, starting |
| * at the offset that we just read. Bit 0 indicates that it's |
| * an I/O address, not a memory address, so mask that off. |
| */ |
| *gbasep = base & 1 ? base & ~3 : base & ~15; |
| |
| return 0; |
| } |
| |
| static const struct pch_ops pch9_ops = { |
| .get_spi_base = pch9_get_spi_base, |
| .get_gpio_base = pch9_get_gpio_base, |
| }; |
| |
| static const struct udevice_id pch9_ids[] = { |
| { .compatible = "intel,pch9" }, |
| { } |
| }; |
| |
| U_BOOT_DRIVER(pch9_drv) = { |
| .name = "intel-pch9", |
| .id = UCLASS_PCH, |
| .of_match = pch9_ids, |
| .ops = &pch9_ops, |
| }; |