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Tom Rini83d290c2018-05-06 17:58:06 -04001// SPDX-License-Identifier: GPL-2.0+
wdenk0587dd12002-10-26 17:33:42 +00002/*
3 * (C) Copyright 2001
4 * Wolfgang Denk, DENX Software Engineering, wd@denx.de.
wdenk0587dd12002-10-26 17:33:42 +00005 */
6
wdenk0587dd12002-10-26 17:33:42 +00007#include <common.h>
8#include <command.h>
Simon Glass199e87c2015-04-20 12:37:17 -06009#include <errno.h>
wdenk0587dd12002-10-26 17:33:42 +000010#include <rtc.h>
11
Jon Loeligera5938142007-07-09 18:10:50 -050012#if defined(CONFIG_CMD_DATE) || defined(CONFIG_TIMESTAMP)
wdenk0587dd12002-10-26 17:33:42 +000013
14#define FEBRUARY 2
15#define STARTOFTIME 1970
16#define SECDAY 86400L
17#define SECYR (SECDAY * 365)
18#define leapyear(year) ((year) % 4 == 0)
Wolfgang Denk53677ef2008-05-20 16:00:29 +020019#define days_in_year(a) (leapyear(a) ? 366 : 365)
20#define days_in_month(a) (month_days[(a) - 1])
wdenk0587dd12002-10-26 17:33:42 +000021
22static int month_days[12] = {
23 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31
24};
25
Simon Glass36b898b2016-06-19 19:51:00 -060026static int month_offset[] = {
27 0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334
28};
29
wdenk0587dd12002-10-26 17:33:42 +000030/*
31 * This only works for the Gregorian calendar - i.e. after 1752 (in the UK)
32 */
Simon Glass199e87c2015-04-20 12:37:17 -060033int rtc_calc_weekday(struct rtc_time *tm)
wdenk0587dd12002-10-26 17:33:42 +000034{
Simon Glass36b898b2016-06-19 19:51:00 -060035 int leaps_to_date;
36 int last_year;
wdenk0587dd12002-10-26 17:33:42 +000037 int day;
wdenk0587dd12002-10-26 17:33:42 +000038
Simon Glass199e87c2015-04-20 12:37:17 -060039 if (tm->tm_year < 1753)
Simon Glass36b898b2016-06-19 19:51:00 -060040 return -1;
41 last_year = tm->tm_year - 1;
wdenk0587dd12002-10-26 17:33:42 +000042
Simon Glass36b898b2016-06-19 19:51:00 -060043 /* Number of leap corrections to apply up to end of last year */
44 leaps_to_date = last_year / 4 - last_year / 100 + last_year / 400;
wdenk0587dd12002-10-26 17:33:42 +000045
46 /*
47 * This year is a leap year if it is divisible by 4 except when it is
48 * divisible by 100 unless it is divisible by 400
49 *
Simon Glass36b898b2016-06-19 19:51:00 -060050 * e.g. 1904 was a leap year, 1900 was not, 1996 is, and 2000 is.
wdenk0587dd12002-10-26 17:33:42 +000051 */
Simon Glass36b898b2016-06-19 19:51:00 -060052 if (tm->tm_year % 4 == 0 &&
53 ((tm->tm_year % 100 != 0) || (tm->tm_year % 400 == 0)) &&
54 tm->tm_mon > 2) {
55 /* We are past Feb. 29 in a leap year */
56 day = 1;
wdenk0587dd12002-10-26 17:33:42 +000057 } else {
Simon Glass36b898b2016-06-19 19:51:00 -060058 day = 0;
wdenk0587dd12002-10-26 17:33:42 +000059 }
60
Simon Glass36b898b2016-06-19 19:51:00 -060061 day += last_year * 365 + leaps_to_date + month_offset[tm->tm_mon - 1] +
62 tm->tm_mday;
63 tm->tm_wday = day % 7;
Simon Glass199e87c2015-04-20 12:37:17 -060064
65 return 0;
wdenk0587dd12002-10-26 17:33:42 +000066}
67
Simon Glass9f9276c2015-04-20 12:37:18 -060068int rtc_to_tm(int tim, struct rtc_time *tm)
wdenk0587dd12002-10-26 17:33:42 +000069{
Simon Glass36b898b2016-06-19 19:51:00 -060070 register int i;
71 register long hms, day;
wdenk0587dd12002-10-26 17:33:42 +000072
73 day = tim / SECDAY;
74 hms = tim % SECDAY;
75
76 /* Hours, minutes, seconds are easy */
77 tm->tm_hour = hms / 3600;
78 tm->tm_min = (hms % 3600) / 60;
79 tm->tm_sec = (hms % 3600) % 60;
80
81 /* Number of years in days */
Simon Glass36b898b2016-06-19 19:51:00 -060082 for (i = STARTOFTIME; day >= days_in_year(i); i++)
wdenk0587dd12002-10-26 17:33:42 +000083 day -= days_in_year(i);
wdenk0587dd12002-10-26 17:33:42 +000084 tm->tm_year = i;
85
86 /* Number of months in days left */
Simon Glass36b898b2016-06-19 19:51:00 -060087 if (leapyear(tm->tm_year))
wdenk0587dd12002-10-26 17:33:42 +000088 days_in_month(FEBRUARY) = 29;
Simon Glass36b898b2016-06-19 19:51:00 -060089 for (i = 1; day >= days_in_month(i); i++)
wdenk0587dd12002-10-26 17:33:42 +000090 day -= days_in_month(i);
wdenk0587dd12002-10-26 17:33:42 +000091 days_in_month(FEBRUARY) = 28;
92 tm->tm_mon = i;
93
Simon Glass36b898b2016-06-19 19:51:00 -060094 /* Days are what is left over (+1) from all that */
wdenk0587dd12002-10-26 17:33:42 +000095 tm->tm_mday = day + 1;
96
Simon Glass9f9276c2015-04-20 12:37:18 -060097 /* Zero unused fields */
98 tm->tm_yday = 0;
99 tm->tm_isdst = 0;
100
wdenk0587dd12002-10-26 17:33:42 +0000101 /*
102 * Determine the day of week
103 */
Simon Glass9f9276c2015-04-20 12:37:18 -0600104 return rtc_calc_weekday(tm);
wdenk0587dd12002-10-26 17:33:42 +0000105}
106
Simon Glass36b898b2016-06-19 19:51:00 -0600107/*
108 * Converts Gregorian date to seconds since 1970-01-01 00:00:00.
wdenk0587dd12002-10-26 17:33:42 +0000109 * Assumes input in normal date format, i.e. 1980-12-31 23:59:59
110 * => year=1980, mon=12, day=31, hour=23, min=59, sec=59.
111 *
112 * [For the Julian calendar (which was used in Russia before 1917,
113 * Britain & colonies before 1752, anywhere else before 1582,
114 * and is still in use by some communities) leave out the
Simon Glass36b898b2016-06-19 19:51:00 -0600115 * -year / 100 + year / 400 terms, and add 10.]
wdenk0587dd12002-10-26 17:33:42 +0000116 *
117 * This algorithm was first published by Gauss (I think).
118 *
119 * WARNING: this function will overflow on 2106-02-07 06:28:16 on
Simon Glass36b898b2016-06-19 19:51:00 -0600120 * machines where long is 32-bit! (However, as time_t is signed, we
wdenk0587dd12002-10-26 17:33:42 +0000121 * will already get problems at other places on 2038-01-19 03:14:08)
122 */
Simon Glass71420982015-04-20 12:37:19 -0600123unsigned long rtc_mktime(const struct rtc_time *tm)
wdenk0587dd12002-10-26 17:33:42 +0000124{
Simon Glass71420982015-04-20 12:37:19 -0600125 int mon = tm->tm_mon;
126 int year = tm->tm_year;
127 int days, hours;
128
129 mon -= 2;
Simon Glass36b898b2016-06-19 19:51:00 -0600130 if (0 >= (int)mon) { /* 1..12 -> 11, 12, 1..10 */
131 mon += 12; /* Puts Feb last since it has leap day */
wdenk0587dd12002-10-26 17:33:42 +0000132 year -= 1;
133 }
134
Simon Glass71420982015-04-20 12:37:19 -0600135 days = (unsigned long)(year / 4 - year / 100 + year / 400 +
136 367 * mon / 12 + tm->tm_mday) +
137 year * 365 - 719499;
138 hours = days * 24 + tm->tm_hour;
139 return (hours * 60 + tm->tm_min) * 60 + tm->tm_sec;
wdenk0587dd12002-10-26 17:33:42 +0000140}
141
Jon Loeliger068b60a2007-07-10 10:27:39 -0500142#endif